As shown below:
If the VGS of AO3415 is ±8V, will this circuit burn?
The originally intended function is to enable 12Vout output when enabled, and no output when enabled.
The previous design is used, and I care too much. Today, I found an AO3415 burned under the condition that the output is not connected to the load. Check the manual to see that VGS is ±8V. Is this the reason?
How to modify it
Conner Veröffentlicht am June 30, 2020
It should be the problem of Vgs overrun. If you cannot replace Q1 with another PMOS with a higher Vgs range, you must change the board. Add a series resistor at the D pole of Q2 and divide the voltage with R1 to control the G pole of Q1, so that Vgs is not -12V. Too.
Reynaldo Veröffentlicht am June 30, 2020
You may not change the board for the time being, just change the device and add it next time you change the board.
Linnea Veröffentlicht am June 30, 2020
The maximum value of the gate-source voltage when q2 is turned on to Q1 is 8V. If it exceeds the 8V safety limit, it will be burned. Disconnect a resistor within 10k from q2 to 3 in series, reducing the gate-source voltage of Q1 to avoid exceeding 8v.
Ronaldo Veröffentlicht am June 30, 2020
The maximum gate-source voltage of Q1 is 12V, which exceeds the safety limit of 8V.
Connect a resistance greater than 5K (such as 5.6k or 6.2k) to the drain (pin 3) of Q2, so that the maximum gate-source voltage of Q1 does not exceed 8V, ensuring safety.
